定積分・広義積分計算機
定積分と広義積分を手順を追って計算する
この計算機は、定積分(すなわち上下限のある積分)を、広義積分も含めて、解法手順を示しながら計算を試みます。
Solution
Your input: calculate $$$\int_{0}^{-1}\left( - 4 x^{3} + x^{2} \right)dx$$$
First, calculate the corresponding indefinite integral: $$$\int{\left(- 4 x^{3} + x^{2}\right)d x}=x^{3} \left(\frac{1}{3} - x\right)$$$ (for steps, see indefinite integral calculator)
According to the Fundamental Theorem of Calculus, $$$\int_a^b F(x) dx=f(b)-f(a)$$$, so just evaluate the integral at the endpoints, and that's the answer.
$$$\left(x^{3} \left(\frac{1}{3} - x\right)\right)|_{\left(x=-1\right)}=- \frac{4}{3}$$$
$$$\left(x^{3} \left(\frac{1}{3} - x\right)\right)|_{\left(x=0\right)}=0$$$
$$$\int_{0}^{-1}\left( - 4 x^{3} + x^{2} \right)dx=\left(x^{3} \left(\frac{1}{3} - x\right)\right)|_{\left(x=-1\right)}-\left(x^{3} \left(\frac{1}{3} - x\right)\right)|_{\left(x=0\right)}=- \frac{4}{3}$$$
Answer: $$$\int_{0}^{-1}\left( - 4 x^{3} + x^{2} \right)dx=- \frac{4}{3}\approx -1.33333333333333$$$