Turunan dari $$$\operatorname{atan}{\left(\frac{1}{x} \right)}$$$
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Masukan Anda
Temukan $$$\frac{d}{dx} \left(\operatorname{atan}{\left(\frac{1}{x} \right)}\right)$$$.
Solusi
Fungsi $$$\operatorname{atan}{\left(\frac{1}{x} \right)}$$$ merupakan komposisi $$$f{\left(g{\left(x \right)} \right)}$$$ dari dua fungsi $$$f{\left(u \right)} = \operatorname{atan}{\left(u \right)}$$$ dan $$$g{\left(x \right)} = \frac{1}{x}$$$.
Terapkan aturan rantai $$$\frac{d}{dx} \left(f{\left(g{\left(x \right)} \right)}\right) = \frac{d}{du} \left(f{\left(u \right)}\right) \frac{d}{dx} \left(g{\left(x \right)}\right)$$$:
$${\color{red}\left(\frac{d}{dx} \left(\operatorname{atan}{\left(\frac{1}{x} \right)}\right)\right)} = {\color{red}\left(\frac{d}{du} \left(\operatorname{atan}{\left(u \right)}\right) \frac{d}{dx} \left(\frac{1}{x}\right)\right)}$$Turunan dari arkus tangen adalah $$$\frac{d}{du} \left(\operatorname{atan}{\left(u \right)}\right) = \frac{1}{u^{2} + 1}$$$:
$${\color{red}\left(\frac{d}{du} \left(\operatorname{atan}{\left(u \right)}\right)\right)} \frac{d}{dx} \left(\frac{1}{x}\right) = {\color{red}\left(\frac{1}{u^{2} + 1}\right)} \frac{d}{dx} \left(\frac{1}{x}\right)$$Kembalikan ke variabel semula:
$$\frac{\frac{d}{dx} \left(\frac{1}{x}\right)}{{\color{red}\left(u\right)}^{2} + 1} = \frac{\frac{d}{dx} \left(\frac{1}{x}\right)}{{\color{red}\left(\frac{1}{x}\right)}^{2} + 1}$$Terapkan aturan pangkat $$$\frac{d}{dx} \left(x^{n}\right) = n x^{n - 1}$$$ dengan $$$n = -1$$$:
$$\frac{{\color{red}\left(\frac{d}{dx} \left(\frac{1}{x}\right)\right)}}{1 + \frac{1}{x^{2}}} = \frac{{\color{red}\left(- \frac{1}{x^{2}}\right)}}{1 + \frac{1}{x^{2}}}$$Sederhanakan:
$$- \frac{1}{x^{2} \left(1 + \frac{1}{x^{2}}\right)} = - \frac{1}{x^{2} + 1}$$Dengan demikian, $$$\frac{d}{dx} \left(\operatorname{atan}{\left(\frac{1}{x} \right)}\right) = - \frac{1}{x^{2} + 1}$$$.
Jawaban
$$$\frac{d}{dx} \left(\operatorname{atan}{\left(\frac{1}{x} \right)}\right) = - \frac{1}{x^{2} + 1}$$$A