Calculatrice d’intégrales définies et impropres

La calculatrice essaiera d'évaluer l'intégrale définie (c.-à-d. avec bornes), y compris les intégrales impropres, en affichant les étapes.

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Solution

Your input: calculate $$$\int_{0}^{\pi}\left( \sin^{6}{\left(x \right)} \cos^{3}{\left(x \right)} \right)dx$$$

First, calculate the corresponding indefinite integral: $$$\int{\sin^{6}{\left(x \right)} \cos^{3}{\left(x \right)} d x}=- \frac{\sin^{9}{\left(x \right)}}{9} + \frac{\sin^{7}{\left(x \right)}}{7}$$$ (for steps, see indefinite integral calculator)

According to the Fundamental Theorem of Calculus, $$$\int_a^b F(x) dx=f(b)-f(a)$$$, so just evaluate the integral at the endpoints, and that's the answer.

$$$\left(- \frac{\sin^{9}{\left(x \right)}}{9} + \frac{\sin^{7}{\left(x \right)}}{7}\right)|_{\left(x=\pi\right)}=0$$$

$$$\left(- \frac{\sin^{9}{\left(x \right)}}{9} + \frac{\sin^{7}{\left(x \right)}}{7}\right)|_{\left(x=0\right)}=0$$$

$$$\int_{0}^{\pi}\left( \sin^{6}{\left(x \right)} \cos^{3}{\left(x \right)} \right)dx=\left(- \frac{\sin^{9}{\left(x \right)}}{9} + \frac{\sin^{7}{\left(x \right)}}{7}\right)|_{\left(x=\pi\right)}-\left(- \frac{\sin^{9}{\left(x \right)}}{9} + \frac{\sin^{7}{\left(x \right)}}{7}\right)|_{\left(x=0\right)}=0$$$

Answer: $$$\int_{0}^{\pi}\left( \sin^{6}{\left(x \right)} \cos^{3}{\left(x \right)} \right)dx=0$$$

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Solution