Funktion $$$9 x + \frac{6}{x}$$$ integraali

Määritä $$$\int \left(9 x + \frac{6}{x}\right)\, dx$$$.

Integroi termi kerrallaan:

$${\color{red}{\int{\left(9 x + \frac{6}{x}\right)d x}}} = {\color{red}{\left(\int{\frac{6}{x} d x} + \int{9 x d x}\right)}}$$

Sovella vakiokertoimen sääntöä $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ käyttäen $$$c=6$$$ ja $$$f{\left(x \right)} = \frac{1}{x}$$$:

$$\int{9 x d x} + {\color{red}{\int{\frac{6}{x} d x}}} = \int{9 x d x} + {\color{red}{\left(6 \int{\frac{1}{x} d x}\right)}}$$

Funktion $$$\frac{1}{x}$$$ integraali on $$$\int{\frac{1}{x} d x} = \ln{\left(\left|{x}\right| \right)}$$$:

$$\int{9 x d x} + 6 {\color{red}{\int{\frac{1}{x} d x}}} = \int{9 x d x} + 6 {\color{red}{\ln{\left(\left|{x}\right| \right)}}}$$

Sovella vakiokertoimen sääntöä $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ käyttäen $$$c=9$$$ ja $$$f{\left(x \right)} = x$$$:

$$6 \ln{\left(\left|{x}\right| \right)} + {\color{red}{\int{9 x d x}}} = 6 \ln{\left(\left|{x}\right| \right)} + {\color{red}{\left(9 \int{x d x}\right)}}$$

Sovella potenssisääntöä $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ käyttäen $$$n=1$$$:

$$6 \ln{\left(\left|{x}\right| \right)} + 9 {\color{red}{\int{x d x}}}=6 \ln{\left(\left|{x}\right| \right)} + 9 {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=6 \ln{\left(\left|{x}\right| \right)} + 9 {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

Näin ollen,

$$\int{\left(9 x + \frac{6}{x}\right)d x} = \frac{9 x^{2}}{2} + 6 \ln{\left(\left|{x}\right| \right)}$$

Lisää integrointivakio:

$$\int{\left(9 x + \frac{6}{x}\right)d x} = \frac{9 x^{2}}{2} + 6 \ln{\left(\left|{x}\right| \right)}+C$$

$$$\int \left(9 x + \frac{6}{x}\right)\, dx = \left(\frac{9 x^{2}}{2} + 6 \ln\left(\left|{x}\right|\right)\right) + C$$$A