Integral de $$$6^{- x}$$$

Halla $$$\int 6^{- x}\, dx$$$.

Sea $$$u=- x$$$.

Entonces $$$du=\left(- x\right)^{\prime }dx = - dx$$$ (los pasos pueden verse »), y obtenemos que $$$dx = - du$$$.

Por lo tanto,

$${\color{red}{\int{6^{- x} d x}}} = {\color{red}{\int{\left(- 6^{u}\right)d u}}}$$

Aplica la regla del factor constante $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ con $$$c=-1$$$ y $$$f{\left(u \right)} = 6^{u}$$$:

$${\color{red}{\int{\left(- 6^{u}\right)d u}}} = {\color{red}{\left(- \int{6^{u} d u}\right)}}$$

Apply the exponential rule $$$\int{a^{u} d u} = \frac{a^{u}}{\ln{\left(a \right)}}$$$ with $$$a=6$$$:

$$- {\color{red}{\int{6^{u} d u}}} = - {\color{red}{\frac{6^{u}}{\ln{\left(6 \right)}}}}$$

Recordemos que $$$u=- x$$$:

$$- \frac{6^{{\color{red}{u}}}}{\ln{\left(6 \right)}} = - \frac{6^{{\color{red}{\left(- x\right)}}}}{\ln{\left(6 \right)}}$$

Por lo tanto,

$$\int{6^{- x} d x} = - \frac{6^{- x}}{\ln{\left(6 \right)}}$$

Añade la constante de integración:

$$\int{6^{- x} d x} = - \frac{6^{- x}}{\ln{\left(6 \right)}}+C$$

$$$\int 6^{- x}\, dx = - \frac{6^{- x}}{\ln\left(6\right)} + C$$$A