Integral de $$$\frac{- 21 x - 20}{4 x^{8}}$$$
Calculadora relacionada: Calculadora de integrales definidas e impropias
Tu entrada
Halla $$$\int \frac{- 21 x - 20}{4 x^{8}}\, dx$$$.
Solución
La entrada se reescribe: $$$\int{\frac{- 21 x - 20}{4 x^{8}} d x}=\int{\frac{- \frac{21 x}{4} - 5}{x^{8}} d x}$$$.
Simplificar el integrando:
$${\color{red}{\int{\frac{- \frac{21 x}{4} - 5}{x^{8}} d x}}} = {\color{red}{\int{\left(- \frac{\frac{21 x}{4} + 5}{x^{8}}\right)d x}}}$$
Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=-1$$$ y $$$f{\left(x \right)} = \frac{\frac{21 x}{4} + 5}{x^{8}}$$$:
$${\color{red}{\int{\left(- \frac{\frac{21 x}{4} + 5}{x^{8}}\right)d x}}} = {\color{red}{\left(- \int{\frac{\frac{21 x}{4} + 5}{x^{8}} d x}\right)}}$$
Simplify:
$$- {\color{red}{\int{\frac{\frac{21 x}{4} + 5}{x^{8}} d x}}} = - {\color{red}{\int{\frac{21 x + 20}{4 x^{8}} d x}}}$$
Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=\frac{1}{4}$$$ y $$$f{\left(x \right)} = \frac{21 x + 20}{x^{8}}$$$:
$$- {\color{red}{\int{\frac{21 x + 20}{4 x^{8}} d x}}} = - {\color{red}{\left(\frac{\int{\frac{21 x + 20}{x^{8}} d x}}{4}\right)}}$$
Expand the expression:
$$- \frac{{\color{red}{\int{\frac{21 x + 20}{x^{8}} d x}}}}{4} = - \frac{{\color{red}{\int{\left(\frac{21}{x^{7}} + \frac{20}{x^{8}}\right)d x}}}}{4}$$
Integra término a término:
$$- \frac{{\color{red}{\int{\left(\frac{21}{x^{7}} + \frac{20}{x^{8}}\right)d x}}}}{4} = - \frac{{\color{red}{\left(\int{\frac{20}{x^{8}} d x} + \int{\frac{21}{x^{7}} d x}\right)}}}{4}$$
Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=20$$$ y $$$f{\left(x \right)} = \frac{1}{x^{8}}$$$:
$$- \frac{\int{\frac{21}{x^{7}} d x}}{4} - \frac{{\color{red}{\int{\frac{20}{x^{8}} d x}}}}{4} = - \frac{\int{\frac{21}{x^{7}} d x}}{4} - \frac{{\color{red}{\left(20 \int{\frac{1}{x^{8}} d x}\right)}}}{4}$$
Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=-8$$$:
$$- \frac{\int{\frac{21}{x^{7}} d x}}{4} - 5 {\color{red}{\int{\frac{1}{x^{8}} d x}}}=- \frac{\int{\frac{21}{x^{7}} d x}}{4} - 5 {\color{red}{\int{x^{-8} d x}}}=- \frac{\int{\frac{21}{x^{7}} d x}}{4} - 5 {\color{red}{\frac{x^{-8 + 1}}{-8 + 1}}}=- \frac{\int{\frac{21}{x^{7}} d x}}{4} - 5 {\color{red}{\left(- \frac{x^{-7}}{7}\right)}}=- \frac{\int{\frac{21}{x^{7}} d x}}{4} - 5 {\color{red}{\left(- \frac{1}{7 x^{7}}\right)}}$$
Aplica la regla del factor constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ con $$$c=21$$$ y $$$f{\left(x \right)} = \frac{1}{x^{7}}$$$:
$$- \frac{{\color{red}{\int{\frac{21}{x^{7}} d x}}}}{4} + \frac{5}{7 x^{7}} = - \frac{{\color{red}{\left(21 \int{\frac{1}{x^{7}} d x}\right)}}}{4} + \frac{5}{7 x^{7}}$$
Aplica la regla de la potencia $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=-7$$$:
$$- \frac{21 {\color{red}{\int{\frac{1}{x^{7}} d x}}}}{4} + \frac{5}{7 x^{7}}=- \frac{21 {\color{red}{\int{x^{-7} d x}}}}{4} + \frac{5}{7 x^{7}}=- \frac{21 {\color{red}{\frac{x^{-7 + 1}}{-7 + 1}}}}{4} + \frac{5}{7 x^{7}}=- \frac{21 {\color{red}{\left(- \frac{x^{-6}}{6}\right)}}}{4} + \frac{5}{7 x^{7}}=- \frac{21 {\color{red}{\left(- \frac{1}{6 x^{6}}\right)}}}{4} + \frac{5}{7 x^{7}}$$
Por lo tanto,
$$\int{\frac{- \frac{21 x}{4} - 5}{x^{8}} d x} = \frac{7}{8 x^{6}} + \frac{5}{7 x^{7}}$$
Simplificar:
$$\int{\frac{- \frac{21 x}{4} - 5}{x^{8}} d x} = \frac{49 x + 40}{56 x^{7}}$$
Añade la constante de integración:
$$\int{\frac{- \frac{21 x}{4} - 5}{x^{8}} d x} = \frac{49 x + 40}{56 x^{7}}+C$$
Respuesta
$$$\int \frac{- 21 x - 20}{4 x^{8}}\, dx = \frac{49 x + 40}{56 x^{7}} + C$$$A