# Prime factorization of $992$

The calculator will find the prime factorization of $992$, with steps shown.

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Find the prime factorization of $992$.

### Solution

Start with the number $2$.

Determine whether $992$ is divisible by $2$.

It is divisible, thus, divide $992$ by ${\color{green}2}$: $\frac{992}{2} = {\color{red}496}$.

Determine whether $496$ is divisible by $2$.

It is divisible, thus, divide $496$ by ${\color{green}2}$: $\frac{496}{2} = {\color{red}248}$.

Determine whether $248$ is divisible by $2$.

It is divisible, thus, divide $248$ by ${\color{green}2}$: $\frac{248}{2} = {\color{red}124}$.

Determine whether $124$ is divisible by $2$.

It is divisible, thus, divide $124$ by ${\color{green}2}$: $\frac{124}{2} = {\color{red}62}$.

Determine whether $62$ is divisible by $2$.

It is divisible, thus, divide $62$ by ${\color{green}2}$: $\frac{62}{2} = {\color{red}31}$.

The prime number ${\color{green}31}$ has no other factors then $1$ and ${\color{green}31}$: $\frac{31}{31} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $992 = 2^{5} \cdot 31$.

The prime factorization is $992 = 2^{5} \cdot 31$A.