Prime factorization of $$$876$$$

Find the prime factorization of $$$876$$$.

Start with the number $$$2$$$.

Determine whether $$$876$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$876$$$ by $$${\color{green}2}$$$: $$$\frac{876}{2} = {\color{red}438}$$$.

Determine whether $$$438$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$438$$$ by $$${\color{green}2}$$$: $$$\frac{438}{2} = {\color{red}219}$$$.

Determine whether $$$219$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$219$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$219$$$ by $$${\color{green}3}$$$: $$$\frac{219}{3} = {\color{red}73}$$$.

The prime number $$${\color{green}73}$$$ has no other factors then $$$1$$$ and $$${\color{green}73}$$$: $$$\frac{73}{73} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$876 = 2^{2} \cdot 3 \cdot 73$$$.

The prime factorization is $$$876 = 2^{2} \cdot 3 \cdot 73$$$A.