# Prime factorization of $4932$

The calculator will find the prime factorization of $4932$, with steps shown.

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Find the prime factorization of $4932$.

### Solution

Start with the number $2$.

Determine whether $4932$ is divisible by $2$.

It is divisible, thus, divide $4932$ by ${\color{green}2}$: $\frac{4932}{2} = {\color{red}2466}$.

Determine whether $2466$ is divisible by $2$.

It is divisible, thus, divide $2466$ by ${\color{green}2}$: $\frac{2466}{2} = {\color{red}1233}$.

Determine whether $1233$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $1233$ is divisible by $3$.

It is divisible, thus, divide $1233$ by ${\color{green}3}$: $\frac{1233}{3} = {\color{red}411}$.

Determine whether $411$ is divisible by $3$.

It is divisible, thus, divide $411$ by ${\color{green}3}$: $\frac{411}{3} = {\color{red}137}$.

The prime number ${\color{green}137}$ has no other factors then $1$ and ${\color{green}137}$: $\frac{137}{137} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $4932 = 2^{2} \cdot 3^{2} \cdot 137$.

The prime factorization is $4932 = 2^{2} \cdot 3^{2} \cdot 137$A.