Prime factorization of $$$4932$$$

Find the prime factorization of $$$4932$$$.

Start with the number $$$2$$$.

Determine whether $$$4932$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4932$$$ by $$${\color{green}2}$$$: $$$\frac{4932}{2} = {\color{red}2466}$$$.

Determine whether $$$2466$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2466$$$ by $$${\color{green}2}$$$: $$$\frac{2466}{2} = {\color{red}1233}$$$.

Determine whether $$$1233$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$1233$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$1233$$$ by $$${\color{green}3}$$$: $$$\frac{1233}{3} = {\color{red}411}$$$.

Determine whether $$$411$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$411$$$ by $$${\color{green}3}$$$: $$$\frac{411}{3} = {\color{red}137}$$$.

The prime number $$${\color{green}137}$$$ has no other factors then $$$1$$$ and $$${\color{green}137}$$$: $$$\frac{137}{137} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4932 = 2^{2} \cdot 3^{2} \cdot 137$$$.

The prime factorization is $$$4932 = 2^{2} \cdot 3^{2} \cdot 137$$$A.