Prime factorization of $$$4780$$$

Find the prime factorization of $$$4780$$$.

Start with the number $$$2$$$.

Determine whether $$$4780$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$4780$$$ by $$${\color{green}2}$$$: $$$\frac{4780}{2} = {\color{red}2390}$$$.

Determine whether $$$2390$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$2390$$$ by $$${\color{green}2}$$$: $$$\frac{2390}{2} = {\color{red}1195}$$$.

Determine whether $$$1195$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$1195$$$ is divisible by $$$3$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$5$$$.

Determine whether $$$1195$$$ is divisible by $$$5$$$.

It is divisible, thus, divide $$$1195$$$ by $$${\color{green}5}$$$: $$$\frac{1195}{5} = {\color{red}239}$$$.

The prime number $$${\color{green}239}$$$ has no other factors then $$$1$$$ and $$${\color{green}239}$$$: $$$\frac{239}{239} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4780 = 2^{2} \cdot 5 \cdot 239$$$.

The prime factorization is $$$4780 = 2^{2} \cdot 5 \cdot 239$$$A.