Prime factorization of $$$432$$$
Your Input
Find the prime factorization of $$$432$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$432$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$432$$$ by $$${\color{green}2}$$$: $$$\frac{432}{2} = {\color{red}216}$$$.
Determine whether $$$216$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$216$$$ by $$${\color{green}2}$$$: $$$\frac{216}{2} = {\color{red}108}$$$.
Determine whether $$$108$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$108$$$ by $$${\color{green}2}$$$: $$$\frac{108}{2} = {\color{red}54}$$$.
Determine whether $$$54$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$54$$$ by $$${\color{green}2}$$$: $$$\frac{54}{2} = {\color{red}27}$$$.
Determine whether $$$27$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$27$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$27$$$ by $$${\color{green}3}$$$: $$$\frac{27}{3} = {\color{red}9}$$$.
Determine whether $$$9$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$9$$$ by $$${\color{green}3}$$$: $$$\frac{9}{3} = {\color{red}3}$$$.
The prime number $$${\color{green}3}$$$ has no other factors then $$$1$$$ and $$${\color{green}3}$$$: $$$\frac{3}{3} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$432 = 2^{4} \cdot 3^{3}$$$.
Answer
The prime factorization is $$$432 = 2^{4} \cdot 3^{3}$$$A.