Prime factorization of $$$4272$$$
Your Input
Find the prime factorization of $$$4272$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$4272$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$4272$$$ by $$${\color{green}2}$$$: $$$\frac{4272}{2} = {\color{red}2136}$$$.
Determine whether $$$2136$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$2136$$$ by $$${\color{green}2}$$$: $$$\frac{2136}{2} = {\color{red}1068}$$$.
Determine whether $$$1068$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1068$$$ by $$${\color{green}2}$$$: $$$\frac{1068}{2} = {\color{red}534}$$$.
Determine whether $$$534$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$534$$$ by $$${\color{green}2}$$$: $$$\frac{534}{2} = {\color{red}267}$$$.
Determine whether $$$267$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$267$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$267$$$ by $$${\color{green}3}$$$: $$$\frac{267}{3} = {\color{red}89}$$$.
The prime number $$${\color{green}89}$$$ has no other factors then $$$1$$$ and $$${\color{green}89}$$$: $$$\frac{89}{89} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4272 = 2^{4} \cdot 3 \cdot 89$$$.
Answer
The prime factorization is $$$4272 = 2^{4} \cdot 3 \cdot 89$$$A.