Prime factorization of $$$4175$$$
Your Input
Find the prime factorization of $$$4175$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$4175$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$4175$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$4175$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$4175$$$ by $$${\color{green}5}$$$: $$$\frac{4175}{5} = {\color{red}835}$$$.
Determine whether $$$835$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$835$$$ by $$${\color{green}5}$$$: $$$\frac{835}{5} = {\color{red}167}$$$.
The prime number $$${\color{green}167}$$$ has no other factors then $$$1$$$ and $$${\color{green}167}$$$: $$$\frac{167}{167} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$4175 = 5^{2} \cdot 167$$$.
Answer
The prime factorization is $$$4175 = 5^{2} \cdot 167$$$A.