# Prime factorization of $3940$

The calculator will find the prime factorization of $3940$, with steps shown.

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Find the prime factorization of $3940$.

### Solution

Start with the number $2$.

Determine whether $3940$ is divisible by $2$.

It is divisible, thus, divide $3940$ by ${\color{green}2}$: $\frac{3940}{2} = {\color{red}1970}$.

Determine whether $1970$ is divisible by $2$.

It is divisible, thus, divide $1970$ by ${\color{green}2}$: $\frac{1970}{2} = {\color{red}985}$.

Determine whether $985$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $985$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $985$ is divisible by $5$.

It is divisible, thus, divide $985$ by ${\color{green}5}$: $\frac{985}{5} = {\color{red}197}$.

The prime number ${\color{green}197}$ has no other factors then $1$ and ${\color{green}197}$: $\frac{197}{197} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $3940 = 2^{2} \cdot 5 \cdot 197$.

The prime factorization is $3940 = 2^{2} \cdot 5 \cdot 197$A.