# Prime factorization of $3938$

The calculator will find the prime factorization of $3938$, with steps shown.

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Find the prime factorization of $3938$.

### Solution

Start with the number $2$.

Determine whether $3938$ is divisible by $2$.

It is divisible, thus, divide $3938$ by ${\color{green}2}$: $\frac{3938}{2} = {\color{red}1969}$.

Determine whether $1969$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $1969$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $1969$ is divisible by $5$.

Since it is not divisible, move to the next prime number.

The next prime number is $7$.

Determine whether $1969$ is divisible by $7$.

Since it is not divisible, move to the next prime number.

The next prime number is $11$.

Determine whether $1969$ is divisible by $11$.

It is divisible, thus, divide $1969$ by ${\color{green}11}$: $\frac{1969}{11} = {\color{red}179}$.

The prime number ${\color{green}179}$ has no other factors then $1$ and ${\color{green}179}$: $\frac{179}{179} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $3938 = 2 \cdot 11 \cdot 179$.

The prime factorization is $3938 = 2 \cdot 11 \cdot 179$A.