Prime factorization of $$$3925$$$

Find the prime factorization of $$$3925$$$.

Start with the number $$$2$$$.

Determine whether $$$3925$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$3925$$$ is divisible by $$$3$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$5$$$.

Determine whether $$$3925$$$ is divisible by $$$5$$$.

It is divisible, thus, divide $$$3925$$$ by $$${\color{green}5}$$$: $$$\frac{3925}{5} = {\color{red}785}$$$.

Determine whether $$$785$$$ is divisible by $$$5$$$.

It is divisible, thus, divide $$$785$$$ by $$${\color{green}5}$$$: $$$\frac{785}{5} = {\color{red}157}$$$.

The prime number $$${\color{green}157}$$$ has no other factors then $$$1$$$ and $$${\color{green}157}$$$: $$$\frac{157}{157} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3925 = 5^{2} \cdot 157$$$.

The prime factorization is $$$3925 = 5^{2} \cdot 157$$$A.