# Prime factorization of $3732$

The calculator will find the prime factorization of $3732$, with steps shown.

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Find the prime factorization of $3732$.

### Solution

Start with the number $2$.

Determine whether $3732$ is divisible by $2$.

It is divisible, thus, divide $3732$ by ${\color{green}2}$: $\frac{3732}{2} = {\color{red}1866}$.

Determine whether $1866$ is divisible by $2$.

It is divisible, thus, divide $1866$ by ${\color{green}2}$: $\frac{1866}{2} = {\color{red}933}$.

Determine whether $933$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $933$ is divisible by $3$.

It is divisible, thus, divide $933$ by ${\color{green}3}$: $\frac{933}{3} = {\color{red}311}$.

The prime number ${\color{green}311}$ has no other factors then $1$ and ${\color{green}311}$: $\frac{311}{311} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $3732 = 2^{2} \cdot 3 \cdot 311$.

The prime factorization is $3732 = 2^{2} \cdot 3 \cdot 311$A.