Prime factorization of $$$3512$$$

Find the prime factorization of $$$3512$$$.

Start with the number $$$2$$$.

Determine whether $$$3512$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$3512$$$ by $$${\color{green}2}$$$: $$$\frac{3512}{2} = {\color{red}1756}$$$.

Determine whether $$$1756$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1756$$$ by $$${\color{green}2}$$$: $$$\frac{1756}{2} = {\color{red}878}$$$.

Determine whether $$$878$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$878$$$ by $$${\color{green}2}$$$: $$$\frac{878}{2} = {\color{red}439}$$$.

The prime number $$${\color{green}439}$$$ has no other factors then $$$1$$$ and $$${\color{green}439}$$$: $$$\frac{439}{439} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3512 = 2^{3} \cdot 439$$$.

The prime factorization is $$$3512 = 2^{3} \cdot 439$$$A.