# Prime factorization of $3470$

The calculator will find the prime factorization of $3470$, with steps shown.

If the calculator did not compute something or you have identified an error, or you have a suggestion/feedback, please write it in the comments below.

Find the prime factorization of $3470$.

### Solution

Start with the number $2$.

Determine whether $3470$ is divisible by $2$.

It is divisible, thus, divide $3470$ by ${\color{green}2}$: $\frac{3470}{2} = {\color{red}1735}$.

Determine whether $1735$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $1735$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $1735$ is divisible by $5$.

It is divisible, thus, divide $1735$ by ${\color{green}5}$: $\frac{1735}{5} = {\color{red}347}$.

The prime number ${\color{green}347}$ has no other factors then $1$ and ${\color{green}347}$: $\frac{347}{347} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $3470 = 2 \cdot 5 \cdot 347$.

The prime factorization is $3470 = 2 \cdot 5 \cdot 347$A.