Prime factorization of $$$3420$$$
Your Input
Find the prime factorization of $$$3420$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$3420$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$3420$$$ by $$${\color{green}2}$$$: $$$\frac{3420}{2} = {\color{red}1710}$$$.
Determine whether $$$1710$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1710$$$ by $$${\color{green}2}$$$: $$$\frac{1710}{2} = {\color{red}855}$$$.
Determine whether $$$855$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$855$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$855$$$ by $$${\color{green}3}$$$: $$$\frac{855}{3} = {\color{red}285}$$$.
Determine whether $$$285$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$285$$$ by $$${\color{green}3}$$$: $$$\frac{285}{3} = {\color{red}95}$$$.
Determine whether $$$95$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$95$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$95$$$ by $$${\color{green}5}$$$: $$$\frac{95}{5} = {\color{red}19}$$$.
The prime number $$${\color{green}19}$$$ has no other factors then $$$1$$$ and $$${\color{green}19}$$$: $$$\frac{19}{19} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3420 = 2^{2} \cdot 3^{2} \cdot 5 \cdot 19$$$.
Answer
The prime factorization is $$$3420 = 2^{2} \cdot 3^{2} \cdot 5 \cdot 19$$$A.