Prime factorization of $$$3372$$$

Find the prime factorization of $$$3372$$$.

Start with the number $$$2$$$.

Determine whether $$$3372$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$3372$$$ by $$${\color{green}2}$$$: $$$\frac{3372}{2} = {\color{red}1686}$$$.

Determine whether $$$1686$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1686$$$ by $$${\color{green}2}$$$: $$$\frac{1686}{2} = {\color{red}843}$$$.

Determine whether $$$843$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$843$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$843$$$ by $$${\color{green}3}$$$: $$$\frac{843}{3} = {\color{red}281}$$$.

The prime number $$${\color{green}281}$$$ has no other factors then $$$1$$$ and $$${\color{green}281}$$$: $$$\frac{281}{281} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3372 = 2^{2} \cdot 3 \cdot 281$$$.

The prime factorization is $$$3372 = 2^{2} \cdot 3 \cdot 281$$$A.