Prime factorization of $$$3175$$$
Your Input
Find the prime factorization of $$$3175$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$3175$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$3175$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$3175$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$3175$$$ by $$${\color{green}5}$$$: $$$\frac{3175}{5} = {\color{red}635}$$$.
Determine whether $$$635$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$635$$$ by $$${\color{green}5}$$$: $$$\frac{635}{5} = {\color{red}127}$$$.
The prime number $$${\color{green}127}$$$ has no other factors then $$$1$$$ and $$${\color{green}127}$$$: $$$\frac{127}{127} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3175 = 5^{2} \cdot 127$$$.
Answer
The prime factorization is $$$3175 = 5^{2} \cdot 127$$$A.