Prime factorization of $$$3160$$$
Your Input
Find the prime factorization of $$$3160$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$3160$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$3160$$$ by $$${\color{green}2}$$$: $$$\frac{3160}{2} = {\color{red}1580}$$$.
Determine whether $$$1580$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1580$$$ by $$${\color{green}2}$$$: $$$\frac{1580}{2} = {\color{red}790}$$$.
Determine whether $$$790$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$790$$$ by $$${\color{green}2}$$$: $$$\frac{790}{2} = {\color{red}395}$$$.
Determine whether $$$395$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$395$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$395$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$395$$$ by $$${\color{green}5}$$$: $$$\frac{395}{5} = {\color{red}79}$$$.
The prime number $$${\color{green}79}$$$ has no other factors then $$$1$$$ and $$${\color{green}79}$$$: $$$\frac{79}{79} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3160 = 2^{3} \cdot 5 \cdot 79$$$.
Answer
The prime factorization is $$$3160 = 2^{3} \cdot 5 \cdot 79$$$A.