Prime factorization of $$$3141$$$
Your Input
Find the prime factorization of $$$3141$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$3141$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$3141$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$3141$$$ by $$${\color{green}3}$$$: $$$\frac{3141}{3} = {\color{red}1047}$$$.
Determine whether $$$1047$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$1047$$$ by $$${\color{green}3}$$$: $$$\frac{1047}{3} = {\color{red}349}$$$.
The prime number $$${\color{green}349}$$$ has no other factors then $$$1$$$ and $$${\color{green}349}$$$: $$$\frac{349}{349} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3141 = 3^{2} \cdot 349$$$.
Answer
The prime factorization is $$$3141 = 3^{2} \cdot 349$$$A.