Prime factorization of $$$3132$$$

Find the prime factorization of $$$3132$$$.

Start with the number $$$2$$$.

Determine whether $$$3132$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$3132$$$ by $$${\color{green}2}$$$: $$$\frac{3132}{2} = {\color{red}1566}$$$.

Determine whether $$$1566$$$ is divisible by $$$2$$$.

It is divisible, thus, divide $$$1566$$$ by $$${\color{green}2}$$$: $$$\frac{1566}{2} = {\color{red}783}$$$.

Determine whether $$$783$$$ is divisible by $$$2$$$.

Since it is not divisible, move to the next prime number.

The next prime number is $$$3$$$.

Determine whether $$$783$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$783$$$ by $$${\color{green}3}$$$: $$$\frac{783}{3} = {\color{red}261}$$$.

Determine whether $$$261$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$261$$$ by $$${\color{green}3}$$$: $$$\frac{261}{3} = {\color{red}87}$$$.

Determine whether $$$87$$$ is divisible by $$$3$$$.

It is divisible, thus, divide $$$87$$$ by $$${\color{green}3}$$$: $$$\frac{87}{3} = {\color{red}29}$$$.

The prime number $$${\color{green}29}$$$ has no other factors then $$$1$$$ and $$${\color{green}29}$$$: $$$\frac{29}{29} = {\color{red}1}$$$.

Since we have obtained $$$1$$$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$3132 = 2^{2} \cdot 3^{3} \cdot 29$$$.

The prime factorization is $$$3132 = 2^{2} \cdot 3^{3} \cdot 29$$$A.