Prime factorization of $$$2124$$$
Your Input
Find the prime factorization of $$$2124$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$2124$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$2124$$$ by $$${\color{green}2}$$$: $$$\frac{2124}{2} = {\color{red}1062}$$$.
Determine whether $$$1062$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1062$$$ by $$${\color{green}2}$$$: $$$\frac{1062}{2} = {\color{red}531}$$$.
Determine whether $$$531$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$531$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$531$$$ by $$${\color{green}3}$$$: $$$\frac{531}{3} = {\color{red}177}$$$.
Determine whether $$$177$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$177$$$ by $$${\color{green}3}$$$: $$$\frac{177}{3} = {\color{red}59}$$$.
The prime number $$${\color{green}59}$$$ has no other factors then $$$1$$$ and $$${\color{green}59}$$$: $$$\frac{59}{59} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2124 = 2^{2} \cdot 3^{2} \cdot 59$$$.
Answer
The prime factorization is $$$2124 = 2^{2} \cdot 3^{2} \cdot 59$$$A.