Prime factorization of $$$2090$$$
Your Input
Find the prime factorization of $$$2090$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$2090$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$2090$$$ by $$${\color{green}2}$$$: $$$\frac{2090}{2} = {\color{red}1045}$$$.
Determine whether $$$1045$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$1045$$$ is divisible by $$$3$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$5$$$.
Determine whether $$$1045$$$ is divisible by $$$5$$$.
It is divisible, thus, divide $$$1045$$$ by $$${\color{green}5}$$$: $$$\frac{1045}{5} = {\color{red}209}$$$.
Determine whether $$$209$$$ is divisible by $$$5$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$7$$$.
Determine whether $$$209$$$ is divisible by $$$7$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$11$$$.
Determine whether $$$209$$$ is divisible by $$$11$$$.
It is divisible, thus, divide $$$209$$$ by $$${\color{green}11}$$$: $$$\frac{209}{11} = {\color{red}19}$$$.
The prime number $$${\color{green}19}$$$ has no other factors then $$$1$$$ and $$${\color{green}19}$$$: $$$\frac{19}{19} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$2090 = 2 \cdot 5 \cdot 11 \cdot 19$$$.
Answer
The prime factorization is $$$2090 = 2 \cdot 5 \cdot 11 \cdot 19$$$A.