# Prime factorization of $1940$

The calculator will find the prime factorization of $1940$, with steps shown.

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Find the prime factorization of $1940$.

### Solution

Start with the number $2$.

Determine whether $1940$ is divisible by $2$.

It is divisible, thus, divide $1940$ by ${\color{green}2}$: $\frac{1940}{2} = {\color{red}970}$.

Determine whether $970$ is divisible by $2$.

It is divisible, thus, divide $970$ by ${\color{green}2}$: $\frac{970}{2} = {\color{red}485}$.

Determine whether $485$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $485$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $485$ is divisible by $5$.

It is divisible, thus, divide $485$ by ${\color{green}5}$: $\frac{485}{5} = {\color{red}97}$.

The prime number ${\color{green}97}$ has no other factors then $1$ and ${\color{green}97}$: $\frac{97}{97} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $1940 = 2^{2} \cdot 5 \cdot 97$.

The prime factorization is $1940 = 2^{2} \cdot 5 \cdot 97$A.