Prime factorization of $$$1818$$$
Your Input
Find the prime factorization of $$$1818$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$1818$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$1818$$$ by $$${\color{green}2}$$$: $$$\frac{1818}{2} = {\color{red}909}$$$.
Determine whether $$$909$$$ is divisible by $$$2$$$.
Since it is not divisible, move to the next prime number.
The next prime number is $$$3$$$.
Determine whether $$$909$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$909$$$ by $$${\color{green}3}$$$: $$$\frac{909}{3} = {\color{red}303}$$$.
Determine whether $$$303$$$ is divisible by $$$3$$$.
It is divisible, thus, divide $$$303$$$ by $$${\color{green}3}$$$: $$$\frac{303}{3} = {\color{red}101}$$$.
The prime number $$${\color{green}101}$$$ has no other factors then $$$1$$$ and $$${\color{green}101}$$$: $$$\frac{101}{101} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$1818 = 2 \cdot 3^{2} \cdot 101$$$.
Answer
The prime factorization is $$$1818 = 2 \cdot 3^{2} \cdot 101$$$A.