# Prime factorization of $1818$

The calculator will find the prime factorization of $1818$, with steps shown.

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Find the prime factorization of $1818$.

### Solution

Start with the number $2$.

Determine whether $1818$ is divisible by $2$.

It is divisible, thus, divide $1818$ by ${\color{green}2}$: $\frac{1818}{2} = {\color{red}909}$.

Determine whether $909$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $909$ is divisible by $3$.

It is divisible, thus, divide $909$ by ${\color{green}3}$: $\frac{909}{3} = {\color{red}303}$.

Determine whether $303$ is divisible by $3$.

It is divisible, thus, divide $303$ by ${\color{green}3}$: $\frac{303}{3} = {\color{red}101}$.

The prime number ${\color{green}101}$ has no other factors then $1$ and ${\color{green}101}$: $\frac{101}{101} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $1818 = 2 \cdot 3^{2} \cdot 101$.

The prime factorization is $1818 = 2 \cdot 3^{2} \cdot 101$A.