Prime factorization of $$$152$$$
Your Input
Find the prime factorization of $$$152$$$.
Solution
Start with the number $$$2$$$.
Determine whether $$$152$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$152$$$ by $$${\color{green}2}$$$: $$$\frac{152}{2} = {\color{red}76}$$$.
Determine whether $$$76$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$76$$$ by $$${\color{green}2}$$$: $$$\frac{76}{2} = {\color{red}38}$$$.
Determine whether $$$38$$$ is divisible by $$$2$$$.
It is divisible, thus, divide $$$38$$$ by $$${\color{green}2}$$$: $$$\frac{38}{2} = {\color{red}19}$$$.
The prime number $$${\color{green}19}$$$ has no other factors then $$$1$$$ and $$${\color{green}19}$$$: $$$\frac{19}{19} = {\color{red}1}$$$.
Since we have obtained $$$1$$$, we are done.
Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $$$152 = 2^{3} \cdot 19$$$.
Answer
The prime factorization is $$$152 = 2^{3} \cdot 19$$$A.