# Prime factorization of $1330$

The calculator will find the prime factorization of $1330$, with steps shown.

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Find the prime factorization of $1330$.

### Solution

Start with the number $2$.

Determine whether $1330$ is divisible by $2$.

It is divisible, thus, divide $1330$ by ${\color{green}2}$: $\frac{1330}{2} = {\color{red}665}$.

Determine whether $665$ is divisible by $2$.

Since it is not divisible, move to the next prime number.

The next prime number is $3$.

Determine whether $665$ is divisible by $3$.

Since it is not divisible, move to the next prime number.

The next prime number is $5$.

Determine whether $665$ is divisible by $5$.

It is divisible, thus, divide $665$ by ${\color{green}5}$: $\frac{665}{5} = {\color{red}133}$.

Determine whether $133$ is divisible by $5$.

Since it is not divisible, move to the next prime number.

The next prime number is $7$.

Determine whether $133$ is divisible by $7$.

It is divisible, thus, divide $133$ by ${\color{green}7}$: $\frac{133}{7} = {\color{red}19}$.

The prime number ${\color{green}19}$ has no other factors then $1$ and ${\color{green}19}$: $\frac{19}{19} = {\color{red}1}$.

Since we have obtained $1$, we are done.

Now, just count the number of occurences of the divisors (green numbers), and write down the prime factorization: $1330 = 2 \cdot 5 \cdot 7 \cdot 19$.

The prime factorization is $1330 = 2 \cdot 5 \cdot 7 \cdot 19$A.