Approximate $$$\int\limits_{0}^{4} x^{2} \ln\left(x\right)\, dx$$$ with $$$n = 4$$$ using the Riemann sum

The calculator will approximate the integral of $$$x^{2} \ln\left(x\right)$$$ from $$$0$$$ to $$$4$$$ with $$$n = 4$$$ subintervals using the Riemann sum, with steps shown.

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Approximate the integral $$$\int\limits_{0}^{4} x^{2} \ln\left(x\right)\, dx$$$ with $$$n = 4$$$ using the left Riemann sum.


The left Riemann sum (also known as the left endpoint approximation) uses the left endpoint of a subinterval for computing the height of the approximating rectangle:

$$$\int\limits_{a}^{b} f{\left(x \right)}\, dx\approx \Delta x \left(f{\left(x_{0} \right)} + f{\left(x_{1} \right)} + f{\left(x_{2} \right)}+\dots+f{\left(x_{n-2} \right)} + f{\left(x_{n-1} \right)}\right)$$$

where $$$\Delta x = \frac{b - a}{n}$$$.

We have that $$$f{\left(x \right)} = x^{2} \ln\left(x\right)$$$, $$$a = 0$$$, $$$b = 4$$$, and $$$n = 4$$$.

Therefore, $$$\Delta x = \frac{4 - 0}{4} = 1$$$.

Divide the interval $$$\left[0, 4\right]$$$ into $$$n = 4$$$ subintervals of the length $$$\Delta x = 1$$$ with the following endpoints: $$$a = 0$$$, $$$1$$$, $$$2$$$, $$$3$$$, $$$4 = b$$$.

Now, just evaluate the function at the left endpoints of the subintervals.

There is an endpoint that doesn't belong to the domain of the function. Thus, the integral cannot be approximated.


The integral cannot be approximated.