# Derivative of $e^{4 t}$

The calculator will find the derivative of $e^{4 t}$, with steps shown.

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Find $\frac{d}{dt} \left(e^{4 t}\right)$.

### Solution

The function $e^{4 t}$ is the composition $f{\left(g{\left(t \right)} \right)}$ of two functions $f{\left(u \right)} = e^{u}$ and $g{\left(t \right)} = 4 t$.

Apply the chain rule $\frac{d}{dt} \left(f{\left(g{\left(t \right)} \right)}\right) = \frac{d}{du} \left(f{\left(u \right)}\right) \frac{d}{dt} \left(g{\left(t \right)}\right)$:

$${\color{red}\left(\frac{d}{dt} \left(e^{4 t}\right)\right)} = {\color{red}\left(\frac{d}{du} \left(e^{u}\right) \frac{d}{dt} \left(4 t\right)\right)}$$

The derivative of the exponential is $\frac{d}{du} \left(e^{u}\right) = e^{u}$:

$${\color{red}\left(\frac{d}{du} \left(e^{u}\right)\right)} \frac{d}{dt} \left(4 t\right) = {\color{red}\left(e^{u}\right)} \frac{d}{dt} \left(4 t\right)$$

$$e^{{\color{red}\left(u\right)}} \frac{d}{dt} \left(4 t\right) = e^{{\color{red}\left(4 t\right)}} \frac{d}{dt} \left(4 t\right)$$

Apply the constant multiple rule $\frac{d}{dt} \left(c f{\left(t \right)}\right) = c \frac{d}{dt} \left(f{\left(t \right)}\right)$ with $c = 4$ and $f{\left(t \right)} = t$:

$$e^{4 t} {\color{red}\left(\frac{d}{dt} \left(4 t\right)\right)} = e^{4 t} {\color{red}\left(4 \frac{d}{dt} \left(t\right)\right)}$$

Apply the power rule $\frac{d}{dt} \left(t^{n}\right) = n t^{n - 1}$ with $n = 1$, in other words, $\frac{d}{dt} \left(t\right) = 1$:

$$4 e^{4 t} {\color{red}\left(\frac{d}{dt} \left(t\right)\right)} = 4 e^{4 t} {\color{red}\left(1\right)}$$

Thus, $\frac{d}{dt} \left(e^{4 t}\right) = 4 e^{4 t}$.

$\frac{d}{dt} \left(e^{4 t}\right) = 4 e^{4 t}$A