Integral of $$$e$$$
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Your Input
Find $$$\int e\, de$$$.
Solution
Apply the power rule $$$\int e^{n}\, de = \frac{e^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=1$$$:
$${\color{red}{\int{e d e}}}={\color{red}{\frac{e^{1 + 1}}{1 + 1}}}={\color{red}{\left(\frac{e^{2}}{2}\right)}}$$
Therefore,
$$\int{e d e} = \frac{e^{2}}{2}$$
Add the constant of integration:
$$\int{e d e} = \frac{e^{2}}{2}+C$$
Answer
$$$\int e\, de = \frac{e^{2}}{2} + C$$$A
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