Derivative of $$$\frac{\sqrt{2} y}{2}$$$
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Find $$$\frac{d}{dy} \left(\frac{\sqrt{2} y}{2}\right)$$$.
Solution
Apply the constant multiple rule $$$\frac{d}{dy} \left(c f{\left(y \right)}\right) = c \frac{d}{dy} \left(f{\left(y \right)}\right)$$$ with $$$c = \frac{\sqrt{2}}{2}$$$ and $$$f{\left(y \right)} = y$$$:
$${\color{red}\left(\frac{d}{dy} \left(\frac{\sqrt{2} y}{2}\right)\right)} = {\color{red}\left(\frac{\sqrt{2}}{2} \frac{d}{dy} \left(y\right)\right)}$$Apply the power rule $$$\frac{d}{dy} \left(y^{n}\right) = n y^{n - 1}$$$ with $$$n = 1$$$, in other words, $$$\frac{d}{dy} \left(y\right) = 1$$$:
$$\frac{\sqrt{2} {\color{red}\left(\frac{d}{dy} \left(y\right)\right)}}{2} = \frac{\sqrt{2} {\color{red}\left(1\right)}}{2}$$Thus, $$$\frac{d}{dy} \left(\frac{\sqrt{2} y}{2}\right) = \frac{\sqrt{2}}{2}$$$.
Answer
$$$\frac{d}{dy} \left(\frac{\sqrt{2} y}{2}\right) = \frac{\sqrt{2}}{2}$$$A