Derivative of $$$g - 27$$$
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Your Input
Find $$$\frac{d}{dg} \left(g - 27\right)$$$.
Solution
The derivative of a sum/difference is the sum/difference of derivatives:
$${\color{red}\left(\frac{d}{dg} \left(g - 27\right)\right)} = {\color{red}\left(\frac{d}{dg} \left(g\right) - \frac{d}{dg} \left(27\right)\right)}$$Apply the power rule $$$\frac{d}{dg} \left(g^{n}\right) = n g^{n - 1}$$$ with $$$n = 1$$$, in other words, $$$\frac{d}{dg} \left(g\right) = 1$$$:
$${\color{red}\left(\frac{d}{dg} \left(g\right)\right)} - \frac{d}{dg} \left(27\right) = {\color{red}\left(1\right)} - \frac{d}{dg} \left(27\right)$$The derivative of a constant is $$$0$$$:
$$1 - {\color{red}\left(\frac{d}{dg} \left(27\right)\right)} = 1 - {\color{red}\left(0\right)}$$Thus, $$$\frac{d}{dg} \left(g - 27\right) = 1$$$.
Answer
$$$\frac{d}{dg} \left(g - 27\right) = 1$$$A
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