Derivative of $$$1 - \tan{\left(x \right)}$$$
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Your Input
Find $$$\frac{d}{dx} \left(1 - \tan{\left(x \right)}\right)$$$.
Solution
The derivative of a sum/difference is the sum/difference of derivatives:
$${\color{red}\left(\frac{d}{dx} \left(1 - \tan{\left(x \right)}\right)\right)} = {\color{red}\left(\frac{d}{dx} \left(1\right) - \frac{d}{dx} \left(\tan{\left(x \right)}\right)\right)}$$The derivative of a constant is $$$0$$$:
$${\color{red}\left(\frac{d}{dx} \left(1\right)\right)} - \frac{d}{dx} \left(\tan{\left(x \right)}\right) = {\color{red}\left(0\right)} - \frac{d}{dx} \left(\tan{\left(x \right)}\right)$$The derivative of the tangent is $$$\frac{d}{dx} \left(\tan{\left(x \right)}\right) = \sec^{2}{\left(x \right)}$$$:
$$- {\color{red}\left(\frac{d}{dx} \left(\tan{\left(x \right)}\right)\right)} = - {\color{red}\left(\sec^{2}{\left(x \right)}\right)}$$Thus, $$$\frac{d}{dx} \left(1 - \tan{\left(x \right)}\right) = - \sec^{2}{\left(x \right)}$$$.
Answer
$$$\frac{d}{dx} \left(1 - \tan{\left(x \right)}\right) = - \sec^{2}{\left(x \right)}$$$A