Derivative of $$$- x \sin{\left(\frac{1}{2} \right)} + 1$$$
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Your Input
Find $$$\frac{d}{dx} \left(- x \sin{\left(\frac{1}{2} \right)} + 1\right)$$$.
Solution
The derivative of a sum/difference is the sum/difference of derivatives:
$${\color{red}\left(\frac{d}{dx} \left(- x \sin{\left(\frac{1}{2} \right)} + 1\right)\right)} = {\color{red}\left(- \frac{d}{dx} \left(x \sin{\left(\frac{1}{2} \right)}\right) + \frac{d}{dx} \left(1\right)\right)}$$The derivative of a constant is $$$0$$$:
$${\color{red}\left(\frac{d}{dx} \left(1\right)\right)} - \frac{d}{dx} \left(x \sin{\left(\frac{1}{2} \right)}\right) = {\color{red}\left(0\right)} - \frac{d}{dx} \left(x \sin{\left(\frac{1}{2} \right)}\right)$$Apply the constant multiple rule $$$\frac{d}{dx} \left(c f{\left(x \right)}\right) = c \frac{d}{dx} \left(f{\left(x \right)}\right)$$$ with $$$c = \sin{\left(\frac{1}{2} \right)}$$$ and $$$f{\left(x \right)} = x$$$:
$$- {\color{red}\left(\frac{d}{dx} \left(x \sin{\left(\frac{1}{2} \right)}\right)\right)} = - {\color{red}\left(\sin{\left(\frac{1}{2} \right)} \frac{d}{dx} \left(x\right)\right)}$$Apply the power rule $$$\frac{d}{dx} \left(x^{n}\right) = n x^{n - 1}$$$ with $$$n = 1$$$, in other words, $$$\frac{d}{dx} \left(x\right) = 1$$$:
$$- \sin{\left(\frac{1}{2} \right)} {\color{red}\left(\frac{d}{dx} \left(x\right)\right)} = - \sin{\left(\frac{1}{2} \right)} {\color{red}\left(1\right)}$$Thus, $$$\frac{d}{dx} \left(- x \sin{\left(\frac{1}{2} \right)} + 1\right) = - \sin{\left(\frac{1}{2} \right)}$$$.
Answer
$$$\frac{d}{dx} \left(- x \sin{\left(\frac{1}{2} \right)} + 1\right) = - \sin{\left(\frac{1}{2} \right)}$$$A