Derivative of $$$- t \left(a + s\right)$$$ with respect to $$$t$$$
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Your Input
Find $$$\frac{d}{dt} \left(- t \left(a + s\right)\right)$$$.
Solution
Apply the constant multiple rule $$$\frac{d}{dt} \left(c f{\left(t \right)}\right) = c \frac{d}{dt} \left(f{\left(t \right)}\right)$$$ with $$$c = - a - s$$$ and $$$f{\left(t \right)} = t$$$:
$${\color{red}\left(\frac{d}{dt} \left(- t \left(a + s\right)\right)\right)} = {\color{red}\left(\left(- a - s\right) \frac{d}{dt} \left(t\right)\right)}$$Apply the power rule $$$\frac{d}{dt} \left(t^{n}\right) = n t^{n - 1}$$$ with $$$n = 1$$$, in other words, $$$\frac{d}{dt} \left(t\right) = 1$$$:
$$\left(- a - s\right) {\color{red}\left(\frac{d}{dt} \left(t\right)\right)} = \left(- a - s\right) {\color{red}\left(1\right)}$$Thus, $$$\frac{d}{dt} \left(- t \left(a + s\right)\right) = - a - s$$$.
Answer
$$$\frac{d}{dt} \left(- t \left(a + s\right)\right) = - a - s$$$A