Double integral $$$\int\limits_{0}^{2 \pi}\int\limits_{0}^{1} \left(\frac{\sin{\left(\theta \right)}}{15} + \frac{14}{15}\right)^{2}\, dr\, d\theta$$$
Your Input
Calculate $$$\int\limits_{0}^{2 \pi}\int\limits_{0}^{1} \left(\frac{\sin{\left(\theta \right)}}{15} + \frac{14}{15}\right)^{2}\, dr\, d\theta.$$$
Answer
$$$\int\limits_{0}^{2 \pi}\int\limits_{0}^{1} \left(\frac{\sin{\left(\theta \right)}}{15} + \frac{14}{15}\right)^{2}\, dr\, d\theta = \frac{131 \pi}{75}\approx 5.487315168270172$$$A
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