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$$$\left[\begin{array}{cc}1 - \lambda & 0\\0 & - \lambda\end{array}\right]$$$ 的行列式
相關計算器: 代數餘子式矩陣計算器
您的輸入
計算 $$$\left|\begin{array}{cc}1 - \lambda & 0\\0 & - \lambda\end{array}\right|$$$。
解答
2x2 矩陣的行列式為 $$$\left|\begin{array}{cc}a & b\\c & d\end{array}\right| = a d - b c$$$。
$$$\left|\begin{array}{cc}1 - \lambda & 0\\0 & - \lambda\end{array}\right| = \left(1 - \lambda\right)\cdot \left(- \lambda\right) - \left(0\right)\cdot \left(0\right) = \lambda^{2} - \lambda$$$
答案
$$$\left|\begin{array}{cc}1 - \lambda & 0\\0 & - \lambda\end{array}\right| = \lambda \left(\lambda - 1\right)$$$A
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