$$$\sqrt{a} - 1$$$ 對 $$$x$$$ 的積分
您的輸入
求$$$\int \left(\sqrt{a} - 1\right)\, dx$$$。
解答
配合 $$$c=\sqrt{a} - 1$$$,應用常數法則 $$$\int c\, dx = c x$$$:
$${\color{red}{\int{\left(\sqrt{a} - 1\right)d x}}} = {\color{red}{x \left(\sqrt{a} - 1\right)}}$$
因此,
$$\int{\left(\sqrt{a} - 1\right)d x} = x \left(\sqrt{a} - 1\right)$$
加上積分常數:
$$\int{\left(\sqrt{a} - 1\right)d x} = x \left(\sqrt{a} - 1\right)+C$$
答案
$$$\int \left(\sqrt{a} - 1\right)\, dx = x \left(\sqrt{a} - 1\right) + C$$$A
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