$$$\frac{\sin{\left(x \right)}}{\cos{\left(x \right)}}$$$ 的積分
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您的輸入
求$$$\int \frac{\sin{\left(x \right)}}{\cos{\left(x \right)}}\, dx$$$。
解答
令 $$$u=\cos{\left(x \right)}$$$。
則 $$$du=\left(\cos{\left(x \right)}\right)^{\prime }dx = - \sin{\left(x \right)} dx$$$ (步驟見»),並可得 $$$\sin{\left(x \right)} dx = - du$$$。
該積分變為
$${\color{red}{\int{\frac{\sin{\left(x \right)}}{\cos{\left(x \right)}} d x}}} = {\color{red}{\int{\left(- \frac{1}{u}\right)d u}}}$$
套用常數倍法則 $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$,使用 $$$c=-1$$$ 與 $$$f{\left(u \right)} = \frac{1}{u}$$$:
$${\color{red}{\int{\left(- \frac{1}{u}\right)d u}}} = {\color{red}{\left(- \int{\frac{1}{u} d u}\right)}}$$
$$$\frac{1}{u}$$$ 的積分是 $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:
$$- {\color{red}{\int{\frac{1}{u} d u}}} = - {\color{red}{\ln{\left(\left|{u}\right| \right)}}}$$
回顧一下 $$$u=\cos{\left(x \right)}$$$:
$$- \ln{\left(\left|{{\color{red}{u}}}\right| \right)} = - \ln{\left(\left|{{\color{red}{\cos{\left(x \right)}}}}\right| \right)}$$
因此,
$$\int{\frac{\sin{\left(x \right)}}{\cos{\left(x \right)}} d x} = - \ln{\left(\left|{\cos{\left(x \right)}}\right| \right)}$$
加上積分常數:
$$\int{\frac{\sin{\left(x \right)}}{\cos{\left(x \right)}} d x} = - \ln{\left(\left|{\cos{\left(x \right)}}\right| \right)}+C$$
答案
$$$\int \frac{\sin{\left(x \right)}}{\cos{\left(x \right)}}\, dx = - \ln\left(\left|{\cos{\left(x \right)}}\right|\right) + C$$$A