$$$\tan{\left(u \right)} \sec{\left(u \right)}$$$ 的積分
您的輸入
求$$$\int \tan{\left(u \right)} \sec{\left(u \right)}\, du$$$。
解答
$$$\tan{\left(u \right)} \sec{\left(u \right)}$$$ 的積分是 $$$\int{\tan{\left(u \right)} \sec{\left(u \right)} d u} = \sec{\left(u \right)}$$$：
$${\color{red}{\int{\tan{\left(u \right)} \sec{\left(u \right)} d u}}} = {\color{red}{\sec{\left(u \right)}}}$$
因此，
$$\int{\tan{\left(u \right)} \sec{\left(u \right)} d u} = \sec{\left(u \right)}$$
加上積分常數：
$$\int{\tan{\left(u \right)} \sec{\left(u \right)} d u} = \sec{\left(u \right)}+C$$
答案
$$$\int \tan{\left(u \right)} \sec{\left(u \right)}\, du = \sec{\left(u \right)} + C$$$A