$$$\frac{2 \sin{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}}$$$ 的積分
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您的輸入
求$$$\int \frac{2 \sin{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}}\, dx$$$。
解答
重寫分子並將分式拆分:
$${\color{red}{\int{\frac{2 \sin{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}} d x}}} = {\color{red}{\int{\left(1 + \frac{\sin{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}}\right)d x}}}$$
逐項積分:
$${\color{red}{\int{\left(1 + \frac{\sin{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}}\right)d x}}} = {\color{red}{\left(\int{1 d x} + \int{\frac{\sin{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}} d x}\right)}}$$
配合 $$$c=1$$$,應用常數法則 $$$\int c\, dx = c x$$$:
$$\int{\frac{\sin{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}} d x} + {\color{red}{\int{1 d x}}} = \int{\frac{\sin{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}} d x} + {\color{red}{x}}$$
令 $$$u=\sin{\left(x \right)} - \cos{\left(x \right)}$$$。
則 $$$du=\left(\sin{\left(x \right)} - \cos{\left(x \right)}\right)^{\prime }dx = \left(\sin{\left(x \right)} + \cos{\left(x \right)}\right) dx$$$ (步驟見»),並可得 $$$\left(\sin{\left(x \right)} + \cos{\left(x \right)}\right) dx = du$$$。
因此,
$$x + {\color{red}{\int{\frac{\sin{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}} d x}}} = x + {\color{red}{\int{\frac{1}{u} d u}}}$$
$$$\frac{1}{u}$$$ 的積分是 $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:
$$x + {\color{red}{\int{\frac{1}{u} d u}}} = x + {\color{red}{\ln{\left(\left|{u}\right| \right)}}}$$
回顧一下 $$$u=\sin{\left(x \right)} - \cos{\left(x \right)}$$$:
$$x + \ln{\left(\left|{{\color{red}{u}}}\right| \right)} = x + \ln{\left(\left|{{\color{red}{\left(\sin{\left(x \right)} - \cos{\left(x \right)}\right)}}}\right| \right)}$$
因此,
$$\int{\frac{2 \sin{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}} d x} = x + \ln{\left(\left|{\sin{\left(x \right)} - \cos{\left(x \right)}}\right| \right)}$$
化簡:
$$\int{\frac{2 \sin{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}} d x} = x + \ln{\left(\left|{\cos{\left(x + \frac{\pi}{4} \right)}}\right| \right)} + \frac{\ln{\left(2 \right)}}{2}$$
加上積分常數(並從表達式中移除常數項):
$$\int{\frac{2 \sin{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}} d x} = x + \ln{\left(\left|{\cos{\left(x + \frac{\pi}{4} \right)}}\right| \right)}+C$$
答案
$$$\int \frac{2 \sin{\left(x \right)}}{\sin{\left(x \right)} - \cos{\left(x \right)}}\, dx = \left(x + \ln\left(\left|{\cos{\left(x + \frac{\pi}{4} \right)}}\right|\right)\right) + C$$$A