$$$\frac{x^{2}}{x - 7}$$$ 的積分

此計算器將求出 $$$\frac{x^{2}}{x - 7}$$$ 的不定積分(原函數),並顯示步驟。

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您的輸入

$$$\int \frac{x^{2}}{x - 7}\, dx$$$

解答

由於分子次數不小於分母次數,進行多項式長除法(步驟見»):

$${\color{red}{\int{\frac{x^{2}}{x - 7} d x}}} = {\color{red}{\int{\left(x + 7 + \frac{49}{x - 7}\right)d x}}}$$

逐項積分:

$${\color{red}{\int{\left(x + 7 + \frac{49}{x - 7}\right)d x}}} = {\color{red}{\left(\int{7 d x} + \int{x d x} + \int{\frac{49}{x - 7} d x}\right)}}$$

配合 $$$c=7$$$,應用常數法則 $$$\int c\, dx = c x$$$

$$\int{x d x} + \int{\frac{49}{x - 7} d x} + {\color{red}{\int{7 d x}}} = \int{x d x} + \int{\frac{49}{x - 7} d x} + {\color{red}{\left(7 x\right)}}$$

套用冪次法則 $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$,以 $$$n=1$$$

$$7 x + \int{\frac{49}{x - 7} d x} + {\color{red}{\int{x d x}}}=7 x + \int{\frac{49}{x - 7} d x} + {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=7 x + \int{\frac{49}{x - 7} d x} + {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

套用常數倍法則 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$,使用 $$$c=49$$$$$$f{\left(x \right)} = \frac{1}{x - 7}$$$

$$\frac{x^{2}}{2} + 7 x + {\color{red}{\int{\frac{49}{x - 7} d x}}} = \frac{x^{2}}{2} + 7 x + {\color{red}{\left(49 \int{\frac{1}{x - 7} d x}\right)}}$$

$$$u=x - 7$$$

$$$du=\left(x - 7\right)^{\prime }dx = 1 dx$$$ (步驟見»),並可得 $$$dx = du$$$

該積分變為

$$\frac{x^{2}}{2} + 7 x + 49 {\color{red}{\int{\frac{1}{x - 7} d x}}} = \frac{x^{2}}{2} + 7 x + 49 {\color{red}{\int{\frac{1}{u} d u}}}$$

$$$\frac{1}{u}$$$ 的積分是 $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$

$$\frac{x^{2}}{2} + 7 x + 49 {\color{red}{\int{\frac{1}{u} d u}}} = \frac{x^{2}}{2} + 7 x + 49 {\color{red}{\ln{\left(\left|{u}\right| \right)}}}$$

回顧一下 $$$u=x - 7$$$

$$\frac{x^{2}}{2} + 7 x + 49 \ln{\left(\left|{{\color{red}{u}}}\right| \right)} = \frac{x^{2}}{2} + 7 x + 49 \ln{\left(\left|{{\color{red}{\left(x - 7\right)}}}\right| \right)}$$

因此,

$$\int{\frac{x^{2}}{x - 7} d x} = \frac{x^{2}}{2} + 7 x + 49 \ln{\left(\left|{x - 7}\right| \right)}$$

加上積分常數:

$$\int{\frac{x^{2}}{x - 7} d x} = \frac{x^{2}}{2} + 7 x + 49 \ln{\left(\left|{x - 7}\right| \right)}+C$$

答案

$$$\int \frac{x^{2}}{x - 7}\, dx = \left(\frac{x^{2}}{2} + 7 x + 49 \ln\left(\left|{x - 7}\right|\right)\right) + C$$$A


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