$$$\left[\begin{array}{cc}\frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2}\end{array}\right]$$$ 的行最简形

求$$$\left[\begin{array}{cc}\frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2}\end{array}\right]$$$的最简行阶梯形。

将第$$$1$$$行乘以$$$\sqrt{2}$$$: $$$R_{1} = \sqrt{2} R_{1}$$$.

$$$\left[\begin{array}{cc}1 & 1\end{array}\right]$$$

最简行阶梯形为 $$$\left[\begin{array}{cc}1 & 1\end{array}\right]$$$A。