矩阵减法计算器

$\times$
$\times$

解决方案

$\left[\begin{array}{ccc}\color{OrangeRed}{1} & \color{Green}{2} & \color{DarkCyan}{-3}\\\color{BlueViolet}{2} & \color{Blue}{-3} & \color{Brown}{-5}\\\color{DarkMagenta}{1} & \color{Purple}{7} & \color{Violet}{1}\end{array}\right] - \left[\begin{array}{ccc}\color{OrangeRed}{2} & \color{Green}{-3} & \color{DarkCyan}{0}\\\color{BlueViolet}{1} & \color{Blue}{1} & \color{Brown}{5}\\\color{DarkMagenta}{1} & \color{Purple}{0} & \color{Violet}{-1}\end{array}\right] = \left[\begin{array}{ccc}\color{OrangeRed}{\left(1\right)} - \color{OrangeRed}{\left(2\right)} & \color{Green}{\left(2\right)} - \color{Green}{\left(-3\right)} & \color{DarkCyan}{\left(-3\right)} - \color{DarkCyan}{\left(0\right)}\\\color{BlueViolet}{\left(2\right)} - \color{BlueViolet}{\left(1\right)} & \color{Blue}{\left(-3\right)} - \color{Blue}{\left(1\right)} & \color{Brown}{\left(-5\right)} - \color{Brown}{\left(5\right)}\\\color{DarkMagenta}{\left(1\right)} - \color{DarkMagenta}{\left(1\right)} & \color{Purple}{\left(7\right)} - \color{Purple}{\left(0\right)} & \color{Violet}{\left(1\right)} - \color{Violet}{\left(-1\right)}\end{array}\right] = \left[\begin{array}{ccc}-1 & 5 & -3\\1 & -4 & -10\\0 & 7 & 2\end{array}\right]$

回答

$\left[\begin{array}{ccc}1 & 2 & -3\\2 & -3 & -5\\1 & 7 & 1\end{array}\right] - \left[\begin{array}{ccc}2 & -3 & 0\\1 & 1 & 5\\1 & 0 & -1\end{array}\right] = \left[\begin{array}{ccc}-1 & 5 & -3\\1 & -4 & -10\\0 & 7 & 2\end{array}\right]$A