$$$x \cos{\left(\pi n x \right)}$$$ 关于$$$x$$$的积分
您的输入
求$$$\int x \cos{\left(\pi n x \right)}\, dx$$$。
解答
对于积分$$$\int{x \cos{\left(\pi n x \right)} d x}$$$,使用分部积分法$$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$。
设 $$$\operatorname{u}=x$$$ 和 $$$\operatorname{dv}=\cos{\left(\pi n x \right)} dx$$$。
则 $$$\operatorname{du}=\left(x\right)^{\prime }dx=1 dx$$$ (步骤见 »),并且 $$$\operatorname{v}=\int{\cos{\left(\pi n x \right)} d x}=\frac{\sin{\left(\pi n x \right)}}{\pi n}$$$ (步骤见 »)。
所以,
$${\color{red}{\int{x \cos{\left(\pi n x \right)} d x}}}={\color{red}{\left(x \cdot \frac{\sin{\left(\pi n x \right)}}{\pi n}-\int{\frac{\sin{\left(\pi n x \right)}}{\pi n} \cdot 1 d x}\right)}}={\color{red}{\left(- \int{\frac{\sin{\left(\pi n x \right)}}{\pi n} d x} + \frac{x \sin{\left(\pi n x \right)}}{\pi n}\right)}}$$
对 $$$c=\frac{1}{\pi n}$$$ 和 $$$f{\left(x \right)} = \sin{\left(\pi n x \right)}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$:
$$- {\color{red}{\int{\frac{\sin{\left(\pi n x \right)}}{\pi n} d x}}} + \frac{x \sin{\left(\pi n x \right)}}{\pi n} = - {\color{red}{\frac{\int{\sin{\left(\pi n x \right)} d x}}{\pi n}}} + \frac{x \sin{\left(\pi n x \right)}}{\pi n}$$
设$$$u=\pi n x$$$。
则$$$du=\left(\pi n x\right)^{\prime }dx = \pi n dx$$$ (步骤见»),并有$$$dx = \frac{du}{\pi n}$$$。
积分变为
$$\frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\int{\sin{\left(\pi n x \right)} d x}}}}{\pi n} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{\pi n} d u}}}}{\pi n}$$
对 $$$c=\frac{1}{\pi n}$$$ 和 $$$f{\left(u \right)} = \sin{\left(u \right)}$$$ 应用常数倍法则 $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$:
$$\frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{\pi n} d u}}}}{\pi n} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\frac{\int{\sin{\left(u \right)} d u}}{\pi n}}}}{\pi n}$$
正弦函数的积分为 $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:
$$\frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{\pi^{2} n^{2}} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{\pi^{2} n^{2}}$$
回忆一下 $$$u=\pi n x$$$:
$$\frac{x \sin{\left(\pi n x \right)}}{\pi n} + \frac{\cos{\left({\color{red}{u}} \right)}}{\pi^{2} n^{2}} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} + \frac{\cos{\left({\color{red}{\pi n x}} \right)}}{\pi^{2} n^{2}}$$
因此,
$$\int{x \cos{\left(\pi n x \right)} d x} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} + \frac{\cos{\left(\pi n x \right)}}{\pi^{2} n^{2}}$$
化简:
$$\int{x \cos{\left(\pi n x \right)} d x} = \frac{\pi n x \sin{\left(\pi n x \right)} + \cos{\left(\pi n x \right)}}{\pi^{2} n^{2}}$$
加上积分常数:
$$\int{x \cos{\left(\pi n x \right)} d x} = \frac{\pi n x \sin{\left(\pi n x \right)} + \cos{\left(\pi n x \right)}}{\pi^{2} n^{2}}+C$$
答案
$$$\int x \cos{\left(\pi n x \right)}\, dx = \frac{\pi n x \sin{\left(\pi n x \right)} + \cos{\left(\pi n x \right)}}{\pi^{2} n^{2}} + C$$$A