$$$\frac{\sin{\left(x \right)} \cos^{2}{\left(x \right)}}{3}$$$ 的积分

该计算器将求出$$$\frac{\sin{\left(x \right)} \cos^{2}{\left(x \right)}}{3}$$$的积分/原函数,并显示步骤。

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您的输入

$$$\int \frac{\sin{\left(x \right)} \cos^{2}{\left(x \right)}}{3}\, dx$$$

解答

应用降幂公式 $$$\cos^{2}{\left(\alpha \right)} = \frac{\cos{\left(2 \alpha \right)}}{2} + \frac{1}{2}$$$,并令 $$$\alpha=x$$$:

$${\color{red}{\int{\frac{\sin{\left(x \right)} \cos^{2}{\left(x \right)}}{3} d x}}} = {\color{red}{\int{\frac{\left(\cos{\left(2 x \right)} + 1\right) \sin{\left(x \right)}}{6} d x}}}$$

$$$c=\frac{1}{2}$$$$$$f{\left(x \right)} = \frac{\left(\cos{\left(2 x \right)} + 1\right) \sin{\left(x \right)}}{3}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$

$${\color{red}{\int{\frac{\left(\cos{\left(2 x \right)} + 1\right) \sin{\left(x \right)}}{6} d x}}} = {\color{red}{\left(\frac{\int{\frac{\left(\cos{\left(2 x \right)} + 1\right) \sin{\left(x \right)}}{3} d x}}{2}\right)}}$$

Expand the expression:

$$\frac{{\color{red}{\int{\frac{\left(\cos{\left(2 x \right)} + 1\right) \sin{\left(x \right)}}{3} d x}}}}{2} = \frac{{\color{red}{\int{\left(\frac{\sin{\left(x \right)} \cos{\left(2 x \right)}}{3} + \frac{\sin{\left(x \right)}}{3}\right)d x}}}}{2}$$

逐项积分:

$$\frac{{\color{red}{\int{\left(\frac{\sin{\left(x \right)} \cos{\left(2 x \right)}}{3} + \frac{\sin{\left(x \right)}}{3}\right)d x}}}}{2} = \frac{{\color{red}{\left(\int{\frac{\sin{\left(x \right)} \cos{\left(2 x \right)}}{3} d x} + \int{\frac{\sin{\left(x \right)}}{3} d x}\right)}}}{2}$$

$$$c=\frac{1}{3}$$$$$$f{\left(x \right)} = \sin{\left(x \right)}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$

$$\frac{\int{\frac{\sin{\left(x \right)} \cos{\left(2 x \right)}}{3} d x}}{2} + \frac{{\color{red}{\int{\frac{\sin{\left(x \right)}}{3} d x}}}}{2} = \frac{\int{\frac{\sin{\left(x \right)} \cos{\left(2 x \right)}}{3} d x}}{2} + \frac{{\color{red}{\left(\frac{\int{\sin{\left(x \right)} d x}}{3}\right)}}}{2}$$

正弦函数的积分为 $$$\int{\sin{\left(x \right)} d x} = - \cos{\left(x \right)}$$$:

$$\frac{\int{\frac{\sin{\left(x \right)} \cos{\left(2 x \right)}}{3} d x}}{2} + \frac{{\color{red}{\int{\sin{\left(x \right)} d x}}}}{6} = \frac{\int{\frac{\sin{\left(x \right)} \cos{\left(2 x \right)}}{3} d x}}{2} + \frac{{\color{red}{\left(- \cos{\left(x \right)}\right)}}}{6}$$

使用公式 $$$\sin\left(\alpha \right)\cos\left(\beta \right)=\frac{1}{2} \sin\left(\alpha-\beta \right)+\frac{1}{2} \sin\left(\alpha+\beta \right)$$$,取 $$$\alpha=x$$$$$$\beta=2 x$$$,将 $$$\sin\left(x \right)\cos\left(2 x \right)$$$ 重写:

$$- \frac{\cos{\left(x \right)}}{6} + \frac{{\color{red}{\int{\frac{\sin{\left(x \right)} \cos{\left(2 x \right)}}{3} d x}}}}{2} = - \frac{\cos{\left(x \right)}}{6} + \frac{{\color{red}{\int{\left(- \frac{\sin{\left(x \right)}}{6} + \frac{\sin{\left(3 x \right)}}{6}\right)d x}}}}{2}$$

$$$c=\frac{1}{2}$$$$$$f{\left(x \right)} = - \frac{\sin{\left(x \right)}}{3} + \frac{\sin{\left(3 x \right)}}{3}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$

$$- \frac{\cos{\left(x \right)}}{6} + \frac{{\color{red}{\int{\left(- \frac{\sin{\left(x \right)}}{6} + \frac{\sin{\left(3 x \right)}}{6}\right)d x}}}}{2} = - \frac{\cos{\left(x \right)}}{6} + \frac{{\color{red}{\left(\frac{\int{\left(- \frac{\sin{\left(x \right)}}{3} + \frac{\sin{\left(3 x \right)}}{3}\right)d x}}{2}\right)}}}{2}$$

逐项积分:

$$- \frac{\cos{\left(x \right)}}{6} + \frac{{\color{red}{\int{\left(- \frac{\sin{\left(x \right)}}{3} + \frac{\sin{\left(3 x \right)}}{3}\right)d x}}}}{4} = - \frac{\cos{\left(x \right)}}{6} + \frac{{\color{red}{\left(- \int{\frac{\sin{\left(x \right)}}{3} d x} + \int{\frac{\sin{\left(3 x \right)}}{3} d x}\right)}}}{4}$$

$$$c=\frac{1}{3}$$$$$$f{\left(x \right)} = \sin{\left(x \right)}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$

$$- \frac{\cos{\left(x \right)}}{6} + \frac{\int{\frac{\sin{\left(3 x \right)}}{3} d x}}{4} - \frac{{\color{red}{\int{\frac{\sin{\left(x \right)}}{3} d x}}}}{4} = - \frac{\cos{\left(x \right)}}{6} + \frac{\int{\frac{\sin{\left(3 x \right)}}{3} d x}}{4} - \frac{{\color{red}{\left(\frac{\int{\sin{\left(x \right)} d x}}{3}\right)}}}{4}$$

正弦函数的积分为 $$$\int{\sin{\left(x \right)} d x} = - \cos{\left(x \right)}$$$:

$$- \frac{\cos{\left(x \right)}}{6} + \frac{\int{\frac{\sin{\left(3 x \right)}}{3} d x}}{4} - \frac{{\color{red}{\int{\sin{\left(x \right)} d x}}}}{12} = - \frac{\cos{\left(x \right)}}{6} + \frac{\int{\frac{\sin{\left(3 x \right)}}{3} d x}}{4} - \frac{{\color{red}{\left(- \cos{\left(x \right)}\right)}}}{12}$$

$$$c=\frac{1}{3}$$$$$$f{\left(x \right)} = \sin{\left(3 x \right)}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$

$$- \frac{\cos{\left(x \right)}}{12} + \frac{{\color{red}{\int{\frac{\sin{\left(3 x \right)}}{3} d x}}}}{4} = - \frac{\cos{\left(x \right)}}{12} + \frac{{\color{red}{\left(\frac{\int{\sin{\left(3 x \right)} d x}}{3}\right)}}}{4}$$

$$$u=3 x$$$

$$$du=\left(3 x\right)^{\prime }dx = 3 dx$$$ (步骤见»),并有$$$dx = \frac{du}{3}$$$

所以,

$$- \frac{\cos{\left(x \right)}}{12} + \frac{{\color{red}{\int{\sin{\left(3 x \right)} d x}}}}{12} = - \frac{\cos{\left(x \right)}}{12} + \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{3} d u}}}}{12}$$

$$$c=\frac{1}{3}$$$$$$f{\left(u \right)} = \sin{\left(u \right)}$$$ 应用常数倍法则 $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$

$$- \frac{\cos{\left(x \right)}}{12} + \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{3} d u}}}}{12} = - \frac{\cos{\left(x \right)}}{12} + \frac{{\color{red}{\left(\frac{\int{\sin{\left(u \right)} d u}}{3}\right)}}}{12}$$

正弦函数的积分为 $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:

$$- \frac{\cos{\left(x \right)}}{12} + \frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{36} = - \frac{\cos{\left(x \right)}}{12} + \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{36}$$

回忆一下 $$$u=3 x$$$:

$$- \frac{\cos{\left(x \right)}}{12} - \frac{\cos{\left({\color{red}{u}} \right)}}{36} = - \frac{\cos{\left(x \right)}}{12} - \frac{\cos{\left({\color{red}{\left(3 x\right)}} \right)}}{36}$$

因此,

$$\int{\frac{\sin{\left(x \right)} \cos^{2}{\left(x \right)}}{3} d x} = - \frac{\cos{\left(x \right)}}{12} - \frac{\cos{\left(3 x \right)}}{36}$$

加上积分常数:

$$\int{\frac{\sin{\left(x \right)} \cos^{2}{\left(x \right)}}{3} d x} = - \frac{\cos{\left(x \right)}}{12} - \frac{\cos{\left(3 x \right)}}{36}+C$$

答案

$$$\int \frac{\sin{\left(x \right)} \cos^{2}{\left(x \right)}}{3}\, dx = \left(- \frac{\cos{\left(x \right)}}{12} - \frac{\cos{\left(3 x \right)}}{36}\right) + C$$$A


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